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標題:
maths既FACTORIZATION
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發問:
1) 2xy + 6x既2次 -72x既3次y - x 2) z既2次 -16x既2次 +72xy - 81y既2次
最佳解答:
1) 2xy + 6x2 -72x3y - x = x (- 72x2y + 6x + 2y - 1) = x [-2y (36x2 - 1) + 6x - 1] = x [-2y (6x + 1) (6x - 1) + 6x - 1] = x {[-2y (6x + 1) + 1] (6x - 1)} = x (-12xy -2y + 1) (6x - 1) 2) z2 -16x2 +72xy - 81y2 = z2 - (16x2 - 72xy + 81y2) = z2 - (4x - 9y)2 = (z + 4x - 9y) (z - 4x + 9y)
其他解答:
1)2xy+6x2-72x^3y-x x(2y+6x-72x2y-1) 2)z2-16x2+72xy-81y2 z2-(4x+9y)2 (z+4x+9y)(z-4x-9y)
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