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標題:
跪求微積分高手幫我解題
發問:
f(x)=x4-4x3+10x-9 求： 1.increasing intervals 2.decreasing intervals 3.intervals of concave upward 4.intervals of concave downward 5.max or min 6.graph
最佳解答:
y(x) = x^4 - 4x^3 + 10x - 9 = 0=> x = 3.35, -1.653 by computer y'(x) = 2(2x^3 - 6x^2 + 5) = 0x = 2.64, 1.168, -0.810 by computer y"(x) = 12x(x - 2)y"(2.64) > 0 => miny"(1.168) < 0 => maxy"(-0.810) > 0 => minShown as the Figure. 1.increasing intervalsx <= -0.891, x = 1.168 ~ 2.642.decreasing intervalsx = -0.891 ~ 1.168, x >= 2.64 3.intervals of concave upwardx <= 1.168, x >= 1.168 4.intervals of concave downwardx = -0.891 ~ 2.64 5.rel max = y(1.168) = -1.83rel min = y(-0.891) = -14.45rel min = y(2.64) = -7.62 6. 圖片參考：https://s.yimg.com/rk/AD06198854/o/638104097.png
其他解答:
跪求微積分高手幫我解題
發問:
f(x)=x4-4x3+10x-9 求： 1.increasing intervals 2.decreasing intervals 3.intervals of concave upward 4.intervals of concave downward 5.max or min 6.graph
最佳解答:
y(x) = x^4 - 4x^3 + 10x - 9 = 0=> x = 3.35, -1.653 by computer y'(x) = 2(2x^3 - 6x^2 + 5) = 0x = 2.64, 1.168, -0.810 by computer y"(x) = 12x(x - 2)y"(2.64) > 0 => miny"(1.168) < 0 => maxy"(-0.810) > 0 => minShown as the Figure. 1.increasing intervalsx <= -0.891, x = 1.168 ~ 2.642.decreasing intervalsx = -0.891 ~ 1.168, x >= 2.64 3.intervals of concave upwardx <= 1.168, x >= 1.168 4.intervals of concave downwardx = -0.891 ~ 2.64 5.rel max = y(1.168) = -1.83rel min = y(-0.891) = -14.45rel min = y(2.64) = -7.62 6. 圖片參考：https://s.yimg.com/rk/AD06198854/o/638104097.png
其他解答:
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