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conc.HNO3
Does conc.HNO3 oxidize iron to iron(ll) or iron(lll)ion?
最佳解答:
Fe3+ will be formed eventually NO3- + 2H+ + e- -->NO2 + H2O Ecell = +0.8V Fe-->Fe2+ + 2e- Ecell = -0.44V Fe + 4HNO3-->Fe(NO3)2 + 2NO2 + 2H2O Ecell = +0.8-(-0.44)=+1.24V NO3- + 4H+ + 3e- -->NO + 2H2O Ecell = +0.96V Fe2+ -->Fe3+ + e- Ecell = +0.77V 3Fe(NO3)2 + 4HNO3-->3Fe(NO3)3 + NO + 2H2O Ecell = +0.96-0.77=+0.19V
其他解答:
Since concentrated nitric acid is a strong oxidizing agent. It will oxidize iron into iron (III) directly and give brown nitrogen dioxide gas. Equation: Fe (s) + 6HNO3 (aq) ---} Fe(NO3)3 (aq) + 3NO2 (g) + 3H2O (l) More-to-know: Dilute nitric acid and concentrated sulphuric acid also perform similar reactions. Hope my explanations help.|||||it oxidize iron to iron(ll) NO3^ - + 2H^+ + e^ - →NO2 +H2O Fe → Fe^2+ + 2e^ - 4HNO3 +Fe → 2NO2 + 2H20 + Fe(NO3)2
conc.HNO3
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發問:Does conc.HNO3 oxidize iron to iron(ll) or iron(lll)ion?
最佳解答:
Fe3+ will be formed eventually NO3- + 2H+ + e- -->NO2 + H2O Ecell = +0.8V Fe-->Fe2+ + 2e- Ecell = -0.44V Fe + 4HNO3-->Fe(NO3)2 + 2NO2 + 2H2O Ecell = +0.8-(-0.44)=+1.24V NO3- + 4H+ + 3e- -->NO + 2H2O Ecell = +0.96V Fe2+ -->Fe3+ + e- Ecell = +0.77V 3Fe(NO3)2 + 4HNO3-->3Fe(NO3)3 + NO + 2H2O Ecell = +0.96-0.77=+0.19V
其他解答:
Since concentrated nitric acid is a strong oxidizing agent. It will oxidize iron into iron (III) directly and give brown nitrogen dioxide gas. Equation: Fe (s) + 6HNO3 (aq) ---} Fe(NO3)3 (aq) + 3NO2 (g) + 3H2O (l) More-to-know: Dilute nitric acid and concentrated sulphuric acid also perform similar reactions. Hope my explanations help.|||||it oxidize iron to iron(ll) NO3^ - + 2H^+ + e^ - →NO2 +H2O Fe → Fe^2+ + 2e^ - 4HNO3 +Fe → 2NO2 + 2H20 + Fe(NO3)2
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