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solve for x
1.solve for x (x-b)(x-c) = (a-b)(a-c)2.ax^2 + bx + c (x,a,b,c are integers and a is not 0),has integer roots if a,b,c are consecutive terms in arithmetic sequence,solve for the roots3. find a ,s has real root,the sum of whose squares is a minimum. 4x^2 + 4(a-2)x - 8a^2 + 14a + 31=04.if y = x^2... 顯示更多 1.solve for x (x-b)(x-c) = (a-b)(a-c) 2.ax^2 + bx + c (x,a,b,c are integers and a is not 0),has integer roots if a,b,c are consecutive terms in arithmetic sequence,solve for the roots 3. find a ,s has real root,the sum of whose squares is a minimum. 4x^2 + 4(a-2)x - 8a^2 + 14a + 31=0 4.if y = x^2 -2x - 3 then determine the min value of (y-4)/(x-4)^2
最佳解答:
1) solve for x (x-b)(x-c) = (a-b)(a-c) x^2-x(b+c)+bc = a^2-a(b+c) +bc x^2-a^2 -(x-a)(b+c) = 0 (x-a)(x+a) - (x-a)(b+c) = 0 (x-a)(x+a-b-c) = 0 x = a or x = b+c-a
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solve for x
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發問:1.solve for x (x-b)(x-c) = (a-b)(a-c)2.ax^2 + bx + c (x,a,b,c are integers and a is not 0),has integer roots if a,b,c are consecutive terms in arithmetic sequence,solve for the roots3. find a ,s has real root,the sum of whose squares is a minimum. 4x^2 + 4(a-2)x - 8a^2 + 14a + 31=04.if y = x^2... 顯示更多 1.solve for x (x-b)(x-c) = (a-b)(a-c) 2.ax^2 + bx + c (x,a,b,c are integers and a is not 0),has integer roots if a,b,c are consecutive terms in arithmetic sequence,solve for the roots 3. find a ,s has real root,the sum of whose squares is a minimum. 4x^2 + 4(a-2)x - 8a^2 + 14a + 31=0 4.if y = x^2 -2x - 3 then determine the min value of (y-4)/(x-4)^2
最佳解答:
1) solve for x (x-b)(x-c) = (a-b)(a-c) x^2-x(b+c)+bc = a^2-a(b+c) +bc x^2-a^2 -(x-a)(b+c) = 0 (x-a)(x+a) - (x-a)(b+c) = 0 (x-a)(x+a-b-c) = 0 x = a or x = b+c-a
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