close
標題:
Mathmatics - simplify
發問:
How to simplify the following question? [(a)(a)...(a)] / (a+a+...+a) = ? Note: [(a)(a)...(a)] means a times and (a+a+...+a) means a terms.
最佳解答:
Q: How to simplify the following question? [(a)(a).......(a)]/(a+a+.......+a) ＝ ? Note: [(a)(a)......(a)] means a times and (a+a+......+a) means a terms. Sol: [(a)(a)......(a)]/(a+a+......+a) ＝ aa/[(a)(a)] ＝ aa/a2 ＝ a(a-2) Ans: a(a-2)
其他解答:
[(a)(a)...(a)] / (a+a+...+a) = a^n/na=(a^(n-1))/n
Mathmatics - simplify
發問:
How to simplify the following question? [(a)(a)...(a)] / (a+a+...+a) = ? Note: [(a)(a)...(a)] means a times and (a+a+...+a) means a terms.
最佳解答:
Q: How to simplify the following question? [(a)(a).......(a)]/(a+a+.......+a) ＝ ? Note: [(a)(a)......(a)] means a times and (a+a+......+a) means a terms. Sol: [(a)(a)......(a)]/(a+a+......+a) ＝ aa/[(a)(a)] ＝ aa/a2 ＝ a(a-2) Ans: a(a-2)
其他解答:
[(a)(a)...(a)] / (a+a+...+a) = a^n/na=(a^(n-1))/n
此文章來自奇摩知識+如有不便請留言告知
文章標籤
全站熱搜
留言列表
